3x^2-x-93x=0

Solution for 3x^2-x-93x=0 equation:

3x^2-x-93x=0

We add all the numbers together, and all the variables

3x^2-94x=0

a = 3; b = -94; c = 0;
Δ = b2-4ac
Δ = -942-4·3·0
Δ = 8836
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{8836}=94$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-94)-94}{2*3}=\frac{0}{6}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-94)+94}{2*3}=\frac{188}{6}
=31+1/3
$